600 e sanford street

The property you are inquiring about is located in Lake Alfred, FL in the East area of Polk County. This is just a gem in the easy-access area of Lake Alfred. Located on a corner lot of 100x141 with privacy fence, screened patio for entertaining around the pool. This beautiful 3 bedroom, 2 bathroom home, with open floorplan and durable tile throughout, nice fireplace in the gathering area, with new kitchen granite-topping, plus an additional flex room for lifestyle convenience, two-car garage, and a full-service house generator. Fabulous value in NO HOA! **Agents, please see MLS remarks.**